Question

if one of the zeros of polynomial ax square - 5 x + 6 is 5 then find the value of a​

Answer 1

$\text{5 is one of the zeroes of }ax^2 - 5x + 6 = 0 \\ \\ a \times {5}^{2} - 5 \times 5 + 6 = 0 \\ \\ 25a - 25 + 6 = 0 \\ \\ 25a - 19 = 0 \\ \\ 25a = 19 \\ \\ a = \frac{19}{25}$

Answer 2

Answer:

→ $a = \frac{19}{25}$

Step-by-step explanation:

$\begin{lgathered}\text{5 is one of the zeroes of }ax^2 - 5x + 6 = 0 \\ \\ a \times {5}^{2} - 5 \times 5 + 6 = 0 \\ \\ 25a - 25 + 6 = 0 \\ \\ 25a - 19 = 0 \\ \\ 25a = 19 \\ \\ a = \frac{19}{25}\end{lgathered}$