Question

if one of the zeros of polynomial f(x) = 5x²+13x+ k is reciprocal of the other, then value of k will be
(a) 0
(b) 1/5
(c) 5
(d). 6
please tell fast....NO SPAM PLS​

Answer 1

Answer:

$\huge{\boxed{\rm{\blue{K=5}}}}$

Step-by-step explanation:

Given :-

one of the zeros of polynomial f(x) = 5x²+13x+ k is reciprocal of the other

To find:-

Find the value of K

Solution:-

Given polynomial f(x)=5x²+13x+ k

On comparing with the standard quadratic polynomial ax²+bx+c

a=5;b=13;c=k

Let one of the zeroes be A

then other zero =1/A

Now

Sum of the zeroes

=A+1/A=-b/a

=>A+1/A=-13/5-----(1)

Product of the zeroes

=>A(1/A)=c/a

=>1=k/5

=>1×5=K

=>K=5

Answer:-

The value of K=5