Question

if one of the zeros of polynomial p(x) =x^2+3kx+8k is 2, then find the value of k and the other zero​

Answer 1

Answer:

2/7

Step-by-step explanation:

if 2 is zeros of given p(x)

then p(2) = 0;

2²+3*2*k + 8*k = 0;

4+ 14 k = 0;

k = 4/14;

k = 2/7. answer