Question

If one of the zeros of quadratic polynomial  
2 k 1 x kx 1    is "-3" then find the
value of k.

Answer 1

Answer:

Given −3 is the zero of the polynomial (k−1)x

2

+kx+1

So −3 must satisfy the equation (k−1)x

2

+kx+1=0

⟹(k−1)(−3)

2

+k(−3)+1=0

⟹9(k−1)−3k+1=0

⟹9k−9−3k+1=0

⟹6k=8

⟹k= 4/3