if one of the zeros of quadratic polynomial K - 1 X square + 1 is minus 3 then the value of k
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Let p(x) = k - 1x^2 + 1
One of the zeroes is -3
p(-3) = k - 1*(-3)^2 + 1
p(-3) = k - 9 + 1
p(-3) = k - 8
k - 8 = 0
k = 8
Hope it helps :)
nitakizhakkedath:
you forgot to multiply (k)with 3²
Its k - 1* (-3)^2. Not k*(-3)^2
yes as you only performed -1*3²instead of doing the whole multiplication
Huh?
I mean that in the first step you only multiplied 3² and -1 instead of multiplying 3² with whole of (k-1)
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(k-1)x²+1
=(k-1)3²+1
=9k-9+1
=9k-8
=k=8/9
=(k-1)3²+1
=9k-9+1
=9k-8
=k=8/9
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