Question

if one of the zeros of quadratic polynomial (K - 1) X square + kx + 1 is - 3 then the value of k is what​

Answer 1

as -3 is a zero so it will satisfy the equation,

(k-1)x^2+kx+1=0, putting value of x=-3 in this,

(k-1)* (-3)^2 -3k + 1 =0

(k-1)*9 -3k + 1 =0

9k - 9 - 3k +  1 =0

6k=8, k=6/8=3/4.

therefore the value of k is 3/4.

TIP- THE QUESTIONS IN WHICH VALUE IS ASKED THEN WE HAVE TO WRITE THE VALUE IN WORDS WITH THEREFORE LIKE I DID. THIS STATEMENT IS IMPORTANT AS IT CARRIES 1/2 MARKS.

HOPE THIS HELPS:-).

MARK BRAINLIEST ONLY IF IT HELPS.

Answer 2

Step-by-step explanation:

(k- 1)x2 + kx + 1 is -3,then p(-3) = 0

⇒ (k-1)(-3)2 + k(-3) + 1 = 0

⇒ 9(k-1)-3k + 1 = 0

⇒ 9k - 9 - 3k + 1 = 0

⇒ 6k - 8 = 0

∴ k = 4/3