Question

If one of the zeros of quadratic polynomial (k-1)x2+kx+1 is -3then find the value of k

Answer 1

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Answer 2

Answer:-

Thinking Process:-

If ∝ is one of the zeroes of the quadratic polynomial $f(x)=ax^2$ + $bx$ + $c$

Then, $f$(∝) must be equal to 0.

Given:-

One of the zeroes of the quadratic polynomial say $p(x)$ = (k-1)x² + kx + 1 is ₋3

Solution:-

⇒ p (-3) = 0

⇒ (k - 1)(-3)² + k(-3) + 1 = 0

⇒ 9(k - 1) ₋3k + 1 = 0

⇒ 9k ₋ 9 ₋ 3k + 1 = 0

⇒ 6k ₋ 8 = 0

⇒ $k=$ $\frac{4}{3}$

Hence, the value of k is $\frac{4}{3}$