If one of the zeros of the cabic polynomia x3-7x+6 is 2 then the product of
the other two zeroes is.
(a) 2
(b) -2
(c) 3
(d) -3
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Alpha ×Bita×Gama=-d/a; so as one root is 2 and the product is -6 so the product of rest two roots are-6/2=-3. Please mark the answer as brainliest.
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