if one of the zeros of the cubic polynomial ax^3+bx^2+cx+d is 0. then the product of the other two zeros is
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Answered by
5
Answer:
c/a
Step-by-step explanation:
let roots of the equation be p,q,r
For a cubic equation,
Product of roots taken two at a time = c/a
pq+qr+rp= c/a.
One of the root is 0,
Let p=0,
So,
0xq + qxr + 0xr = c/a
0+qr+0 = c/a
qr = c/a.
So the product of other two zeros = c/a
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Answered by
1
Step-by-step explanation:
when x=0
ax^3+bx^2+cx+d=0
it becomes d=0
now equation become
ax^3+bx^2+cx=0
i.e. = ax^2+bx+c=0
product of zeros of the given equation
= c/a
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