Question

If one of the zeros of the cubic polynomial x^3+ax^2+bx+c is -1,then prove that the product of other two zeros is b-a+1

Answer 1

Answer:

In △ABC AB=AC

⇒∠B=∠C (Angles opposite to equal sides are equal)

Now using angle sum property

∠A+∠B+∠C=180

∘

⇒80

∘

+∠C+∠C=180

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⇒2∠C=180

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−80

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⇒∠C=

2

100

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=50

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now ∠C+∠x=180

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(Angles made on straight line (AC) are supplementary)

⇒50

∘

+∠x=180

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⇒∠x=180

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−50

∘

=130

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