if one of the zeros of the polynomial p(x)=2x^3 -kx-3 is 3 than the other zero is
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Answer:
Other zero=√10
Step-by-step explanation:
x=3
p(x)=0
p(x)=2x³-kx-3
2x³-kx-3=0
2(3)³-k(3)-3=0
2(27)-k(3)-3=0
54-3k-3=0
54-3-3k=0
51-3k=0
(-3k)=(-51)
3k=51
k=51/3
k=17
2x³-kx-3=0
2x³-17x-3=0
x(2x²-17-3)=0
2x²-20=0
2x²=20
x²=20/2
x²=10
x=√10
Therefore, the other zero is √10.
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