Question

if one of the zeros of the polynomial p(x) = xSqaure -x+k is 2 then the value of k is​

Answer 1

Step-by-step explanation:

x^2 -x +k =0

put x = 2

4-2 + k = 0

k = -2

Answer 2

x^2 -x-k

since 2 is zero of polynomial p(2) =0

then, we have

2^2-2-k= 0

4-2+k = 0

2+k = 0

k=-2

the value of k=-2