Question

If one of the zeros of the polynomial x×x×x+ax×x+bx+c is -1,then find the product of the other two zeros​

Answer 1

Answer:      d/a

Step-by-step explanation:

$p(x)=x^{3} + ax^{2} + bx + c$

let one of the zeros be $\alpha$ = -1

product of zeros$(\alpha \beta * gama$$)$ = -d/a

$-1 *\beta *gama= -d/a$

$\beta *gama=\frac{-d*-1}{a}$                 ( transferring -1 from LHS to RHS)

product of remaining 2 zeros = d/a

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