Question

if one of the zeros of the quadrartic polynomial x2+3x+k is 2 then the value of k is

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Answer 1

Answer:

k= -7

Step-by-step explanation:

x²+3x+k is the polynomial.

(x-2) is one of the zeroes.

Let α and β be the zeroes.

∴α is 2.

α+β= $\frac{-3}{2}$

β= (-3.5)

k= αβ

k= -7

Answer 2

Answer:

The value of k is -10

Step-by-step explanation:

Given : Quadratic polynomial x^2+3x+kx

2

+3x+k

One of the root is 2

To find : The value of k

Solution :

Let the given quadratic polynomial be f(x)=x^2+3x+kf(x)=x

2

+3x+k

Given one of the zero of the quadratic polynomial is 2.

Hence f(2) = 0

Put x = 2 in f(x), we get

f(2)=2^2+3(2)+kf(2)=2

2

+3(2)+k

0=4+6+k0=4+6+k

0=10+k0=10+k

k=-10k=−10

Therefore, The value of k is -10.

hope this helps you...