if one of the zeros of the quadratic polynomial 5x^2-kx+2(k+1) is 1, then find the value of k?
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Answer:
k=(-7)
Step-by-step explanation:
x=1
5x²-kx+2(k+1)=0
5(1)²-k(1)+2(k+1)=0
5-k+2k+2=0
5+2-k+2k=0
k+7=0
k=(-7)
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