Question

If one of the zeros of the quadratic polynomial f(x)=14x²-8k²x-9 is negative of the other,then find the value of k.

Answer 1

Answer:

☆ ANSWER ☆

THERE CAN BE MANY CASES :

X = -1 ,-2,-3.....

LETS TAKE TRY AND ERROR METHOD

CASE 1 :

$p( - 1) = 14( - 1) {}^{2} - 8 {k}^{2} ( - 1) - 9 \\ 0 = 14 + 8 {k}^{2} - 9 \\ 9 - 14 = 8 {k}^{2} \\ - 5 = 8 {k}^{2} \\ - 5 \div 8 = {k}^{2} \\ \sqrt{(5 \div 8)} = k$

CASE 2 :

$p( - 2) = 14( - 2) {}^{2} - 8 {k}^{2} ( - 2) - 9 \\ 0 = 56 + 16 {k}^{2} - 9 \\ 9 - 56 = 16 {k}^{2} \\ - 47 = 16 {k}^{2}$

HOPE THAT HELPS