Question

If one of the zeros of the quadratic polynomial given below is 2 , then value of k is (k-1) xsquare +kx+1is equal to 0 ​

Answer 1

Step-by-step explanation:

Given : One of the zeros of quadratic polynomial (k−1)x

2

+kx+1 is −3

To find : Value of k

Solution : As −3 is one of the zeros of quadratic polynomial (k−1)x

2

+kx+1

⇒ When we substitute −3 in the polynomial , we get 0

⟹(k−1)(−3)

2

+k(−3)+1=0

⟹9k−9−3k+1=0

⟹6k−8=0

or k=

6

8

=

3

4