Question

if one of the zeros of the quadratic polynomial ( k - 1 ) x^2 + kx + 1 is -3 , then find the value of k​

Answer 1

p(X) = ( k - 1 ) x^2 + kx + 1

p(-3) = (k - 1)-3² + k(-3) + 1

p(-3) = 9k - 9 -3k + 1

0 = 6k - 8

-6k = -8

k = -8/-6

k = 4/3

$\red{ PLEASE MARK AS BRAINLIEST }$