If one of the zeros of the quadratic polynomial (k-1)x^2 + kx + 1 is (-3) then find the value of k.
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hi friend,
given one of the zeros of quadratic polynomial (k-1)x2+kx+1 is -3
so when we substitute -3 in the polynomial ,we get 0
→(k-1)(-3)²+k(-3)+1=0
→9k-9-3k+1=0
→6k-8=0
→k=8/6=4/3
I hope this will help u ;)
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