Question

If one of the zeros of the quadratic polynomial (k-1)x^2 + kx + 1 is (-3) then find the value of k.

Answer 1

Answer:

hi friend,

given one of the zeros of quadratic polynomial (k-1)x2+kx+1 is -3

so when we substitute -3 in the polynomial ,we get 0

→(k-1)(-3)²+k(-3)+1=0

→9k-9-3k+1=0

→6k-8=0

→k=8/6=4/3

I hope this will help u ;)

Step-by-step explanation: