Question

If one of the zeros of the quadratic polynomial (k-1)x^2+kx+1 is -3, then find the values of k

Answer 1

put x =-3 in Quadratic polynomial we get
(k-1)(-3)^2 +k(-3)+1 = 0
9k-9 -3k+1 =0
6k-8 =0
k = 8/6 = 4/3 Answer
I hope you got this one

Answer 2

Answer:

Step-by-step explanation:

(k-1)x^2+Kx+1=0

P(x)= -3

(k-1)(-3*- 3)+k-3+1=0

(k-1)9+-3k+1=0

9k-9+-3k+1=0

6k-8=0

6k=8

k=8/6

k=4/3