Question

If one of the zeros of the quadratic Polynomial(k-1)x*x+ kx+1 is -3, then the Value of k is
(a)−4/3
(b)2/3
(c)4/3
(d)−2/3



Here, x*x means square of x

Answer 1

$\underline{\bigstar{\sf\ Given:-}}$

• Polynomial - (k-1)x² + kx+ 1
• zero of the polynomial is -3

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$\underline{\bigstar{\sf\ To\:Find:-}}$

• Value of k

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$\underline{\bigstar{\sf\ Solution:-}}$

Put x = - 3 in the given polynomial

(k - 1) (-3)² + k (-3) + 1 = 0

9k - 9 - 3k + 1 = 0

6k - 8 = 0

6k = 8

⇒ k = $\frac {8}{6}$

⇒ k = $\frac {4}{3}$

Hence, optin (c) is correct.

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