Question

if one of the zeros of the quadratic polynomial (k+1)x²+kx+1 is 2,then find the value of k

Answer 1

Answer:

Hoping that it may help u

Answer 2

Given equation

$(k+1)x^{2} +kx+1=2$

One of the zeroes is 2

Substituting, we get,

$(k+1)4 + 2k + 1 = 2\\4k+4+2k+1=0\\6k+5=0\\\implies \boxed{\boxed{\bold{k = \dfrac{-5}{6} }}}}$