Question

if one of the zeros of the quadratic polynomial (k-1) x2+kx+1 is -3 then the value of k is​

Answer 1

Answer:

$k=\frac{4}{3}$

Step-by-step explanation:

one of the zeros of the quadratic polynomial = -3

quadratic equation => $(k-1)x^{2} + kx+ 1 = 0$

Put x = -3,

$(k-1)(-3)^{2} + k(-3) + 1 = 0 \\ (k-1)(9) -3k +1=0\\ 9k-9-3k+1=0\\ 6k-8=0\\ 6k=8\\ k=\frac{8}{6} \\\\ k = \frac{4}{3}$

Answer 2

Answer:

hope this is helpfull for you