Question

If one of the zeros of the quadratic polynomial (k -1) x² +kx +1 is 13 the find the value of k​

Answer 1

Step-by-step explanation:

Explaination:

(k – 1)² + kx + 1

One zero is – 3, so it must satisfy the equation and make it zero.

∴ (k- 1) (- 3)² + k(-3) + 1 =0

⇒ 9k – 9 – Ik + 1 = 0

⇒ 6k – 8 = 0

⇒ k = \frac{8}{6} = \frac{4}{3}