Question

If one of the zeros of the quadratic polynomial (k – 1)x2 + kx + 1 is (-3), then find the
value of k.

Answer 1

Answer:

UgbctxrxhkbutzrXgvvybkbuftdrszrtighe it is the correct information

Answer 2

❒ Given :

• Supposing one of the zeroes of the given polynomial is (-3)
• Quadratic polynomial = (k - 1)x² + kx + 1

❒ To Find :

• The value of k

❒ Stepwise Answer :

Given that,

P(x) = ( k -1 ) x² + kx + 1 = 0.

➯ p( -3 ) = ( k – 1 ) (-3)² + k (-3) + 1 = 0.

⇒ ( k – 1 ) × 9 -3 k + 1 = 0.

⇒ 9k – 9 – 3k + 1 = 0.

⇒ 6k – 8 = 0.

⇒ 6k = 8.

❒ Therefore,

k = 8/6 = 4/3

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬