Question

If one of the zeros of the quadratic polynomial (k–1)x² + kx + 1 is –3, then the value of k is​

Answer 1

Step-by-step explanation:

=> ( k - 1 ) × 9 -3k + 1 = 0. => 9k - 9 -3k + 1 = 0. => 6k - 8 = 0. Hence, the value of 'k' is founded .

Answer 2

Answer:

(k-1)× -3 -3K +1=0

-3K +3 -3K+1=0

-6K=-4

K=4/6

=2/3.