Question

If one of the zeros of the quadratic polynomial (k-1)x²+kx+q1 is 3,Then find the value of k.How many zeros can a quadratic polynomial have ?​

Answer 1

Answer:

Substitute 3 in equation

(K-1)×9+3k+1=0

9k-9+3k+1=0

12k-8=0

k=2/3

Quadratic can have only 2 zeros

In any polynomial the highest power to which x is raised gives the number of zeros/roots of equation.

Ctrl+Z......

Answer 2

SOLUTION:-

Given:

If one of the zeroes of the quadratic polynomial (k-1)x² + kx +q1 is 3.

To find:

The value of k.

Explanation:

We have,

(k-1)x² + kx +1 & 3 is the zero of the polynomial.

Therefore,

P(3)= (k-1)(3)² + k(3) + 1=0

P(3)= (k-1) 9 + 3k +1=0

P(3)= 9k -9+ 3k+1=0

P(3)= 12k -8 =0

P(3)= 12k= 8

P(3)= k= 8/12

P(3)= k= 2/3

&

There are two zeros have quadratic polynomial.