if one of the zeros of the quadratic polynomial (k - 3)×2 + 12 x + 3 is -3 find k
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Given One of the zeroes of the polynomial is -3
so when X=-3 the Polynomial Become 0
→(k-3)×2 + 12(-3) +3=0
→2k-6 -36 +3=0
→2k -39=0
→2k=39
→k=39/2
so when X=-3 the Polynomial Become 0
→(k-3)×2 + 12(-3) +3=0
→2k-6 -36 +3=0
→2k -39=0
→2k=39
→k=39/2
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