If one of the zeros of the quadratic polynomial (k – 3)x2 + 12x + 3 is −3 find k.
Answers
Answered by
5
Heya user ,
Here is your answer !!
________
Equation ----->
(k – 3)x2 + 12x + 3
one of the zeroes is -3 .
so, according to the question,
(k – 3)x2 + 12x + 3 = 0 .
putting the value of -3 in place of x , we get ,
( k - 3 ) * ( -3 )² + ( 12 * -3 ) + 3 = 0
=> 9( k - 3 ) - 36 + 3 = 0
=> 9k - 27 - 36 + 3 = 0
=> 9k - 60 = 0
=> 9k = 60
=> k = 20/3 = 6.67
________
Hope it helps !!
Here is your answer !!
________
Equation ----->
(k – 3)x2 + 12x + 3
one of the zeroes is -3 .
so, according to the question,
(k – 3)x2 + 12x + 3 = 0 .
putting the value of -3 in place of x , we get ,
( k - 3 ) * ( -3 )² + ( 12 * -3 ) + 3 = 0
=> 9( k - 3 ) - 36 + 3 = 0
=> 9k - 27 - 36 + 3 = 0
=> 9k - 60 = 0
=> 9k = 60
=> k = 20/3 = 6.67
________
Hope it helps !!
Incredible29:
plz msg inbox bhaiyya
we should not chat in the comments box
ok,but i am not so much earned by question to message you dear.Are you in quora?
i have to answer more questions to message you
no
i am not in quora
ok,but that will give you more knowledge,come to quora and search Abhijit Tripathy,if you want
and you can ask your PCM(not bio) doubts to me desr
not interested in bio too
hmm,ok lets talk in message
Similar questions