if one of the zeros of the the equation 5 x square + 13 x Plus a is reciprocal of other find value of a
Answers
Answered by
2
Answer:
a = 5
Step-by-step explanation:
given equation
5x² + 13x + a
given one zero of the polynomial is the reciprocal of the other.
let one zero be α so,
another zero be 1/α
in the equation
5x² + 13x + a
here,
A = 5
B = 13
C = a
we know that,
product of zeros = C/A
so,
ATQ,
α×1/α = a/5
a/5 = 1 [product of zeros = 1]
a = 5
so, value of a in the equation is 5
hope it helps
Answered by
2
Answer:
Your answer is 5.
Step-by-step explanation:
The given equation is 5x² +13x +a
Let alpha is one of the zero of the polynomial then 1/alpha is another zero
Therefore, product of zeroes = c/a
alpha ×1/alpha. = a/5
1 = a/5
5 = a
Hope I was able to help you
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