Question

if one of zero of the quadratic polynomial f(x)=4x2-8kx-9 is negative of the other then find the value of k

Answer 1

Let one roots be x
Then other is -x
Now product of roots = c/a
x(-x)=-9/4
-x sq =-9/4
x= 3/2
Now put it in given polynomial
4(3/2)sq -8k(3/2)-9=0
4×9/4-12k -9=0
9-12k-9=0
k=0ans

Answer 2

The value of k is equal to 0.

Step-by-step explanation:

We have, if one of zero of the quadratic polynomial, $f(x)=4x^2-8kx-9$ is negative of the other. It is required to find the value of k.

Let x is one of the zero of given polynomial and -x is another zero. The sum of zeroes is given by -b/a

$x+(-x)=-\dfrac{-8k}{4}\\\\k=0$

So, the value of k is equal to 0.

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Quadratic equation

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