if one of zeros of polynomial p(x): x2-8x+k is seven times of other then find the value of k
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Answered by
9
let on zero be x
so other zero is 7x
sum of zeroes is 8/2 =4
x+7x=4
8x=4
x=1/2
7x=7/2
k/2=1/2.7/2
k/2=7/4
k=7/2
so other zero is 7x
sum of zeroes is 8/2 =4
x+7x=4
8x=4
x=1/2
7x=7/2
k/2=1/2.7/2
k/2=7/4
k=7/2
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5
if one zero seven times the other then the value of k for given polynomial is 7
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