Math, asked by rajputneha8494, 9 months ago

If one pipe A can fill the tank in 10minutes , then 3 pipes ,each of1/3efficiency of A,can fill the tank in.........

Answers

Answered by imharish
0

Answer:

10 minutes

Step-by-step explanation:

Let A efficiency is 3

Total capacity of tank = efficiency*time

3*10 = 30 capacity

if each of three pipes efficiency is 1

then they will fill the tank

Time = total capacity/ efficiency

three pipes efficiency is = 3*1 = 3

time = 30/3 = 10 minutes

Mark it's brilliant

thanks

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