If one pipe A can fill the tank in 10minutes , then 3 pipes ,each of1/3efficiency of A,can fill the tank in.........
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Answer:
10 minutes
Step-by-step explanation:
Let A efficiency is 3
Total capacity of tank = efficiency*time
3*10 = 30 capacity
if each of three pipes efficiency is 1
then they will fill the tank
Time = total capacity/ efficiency
three pipes efficiency is = 3*1 = 3
time = 30/3 = 10 minutes
Mark it's brilliant
thanks
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