if one rectangular components of force 50N along the horizontal is 30N the other component is
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Answered by
4
Answer:
1500 N is the answer to your question
Answered by
30
Answer:
For rectangular components,
F² = Fx²+Fy²
Let F = 50N and Fx = 30N
50² = 30²+Fy²
Fy² = 2500 −900 = 1600
Fy = 40 N
Hope its helpful
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