If one root is 2 of a quadratic polynomial 2xsquare +3kx+5 find the value of k
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Solution :
Let p(x) = 2x² + 3kx + 5
If x = 2 is a root of p(x) a then ,
p(2) = 0
=> 2(2²) + 3k(2) + 5 = 0
=> 8 + 6k + 5 = 0
=> 13 + 6k = 0
=> 6k = - 13
=> k = -13/6
••••
Let p(x) = 2x² + 3kx + 5
If x = 2 is a root of p(x) a then ,
p(2) = 0
=> 2(2²) + 3k(2) + 5 = 0
=> 8 + 6k + 5 = 0
=> 13 + 6k = 0
=> 6k = - 13
=> k = -13/6
••••
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