Question

If one root is 5 of x2 - 6x + k = 0, then find the value of k.

Answer 1

Step-by-step explanation:

A quadratic equation ax^2+bx+c=0ax2+bx+c=0 has equal roots if

b^2-4ac=0b2−4ac=0             ...(1)

The given equation is

x^2+6x+k=0x2+6x+k=0

Here, a=1, b=6 and c=k. Substitute these values in equation (1).

(6)^2-4(1)(k)=0(6)2−4(1)(k)=0

36-4k=036−4k=0

Subtract 36 from both sides.

-4k=-36−4k=−36

Divide both sides by -4.

k=9k=9

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