Question

If one root of 3x^2 = 8x +(2k +1) is seven times
the other, then the value of k is​

Answer 1

Answer:

3x²-8x+2k+1 a=3, b=-8 ,c=2k+1

suppose the zeroes of the equation are α and β . by the given condition α=7β

as we know , α+β=-b/a

7β+β=-(-8)/3

8β=8/3

β=8/3×1/8=1/3

αβ=c/a

7β×β=2k+1/3

7×1/3×1/3=2k+1/3

7/9=2k+1/3

21/9=2k+1

21/9-1=2k

12/9=2k

4/3=2k

4/6=k

2/3=k

Answer 2

Step-by-step explanation:

Here is the solution.Answer is:one root is1/3 and other is 7/3