if one root of 5 x square + 13 x + k is equal to zero is a reciprocal of the other root then find the value of k
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Answer:
Step-by-step explanation:
f(x) = 5x'2 + 13x + k
Let one root = a
Then other be 1/a
Product of zeros = c/a = k/5
k/5 = a*1/a
k/5 =1
k = 1
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