if one root of 5 x square + 13 x + k
is reciprocal of the Other root find the value of k
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1
Answer:
5
Step-by-step explanation:
Let say roots are a and 1/a
(x-a)(x-1/a) = 0
x^2 -x (a+1/a) + 1 = 0
5x^2 -5x(a+1/a) + 5 = 0
5x^2 + 13x + k = 0
k = 5
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