If one root of 5x^2 13x p=0 be reciprocal of the other then the value of p is
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5x² + 13x + p = 0
here,
a = 5 , b = 13 and c = p.
Product of zeroes = c/a
ß × 1/ß = p/5
p = 5.
here,
a = 5 , b = 13 and c = p.
Product of zeroes = c/a
ß × 1/ß = p/5
p = 5.
Answered by
1
The value of p = 5
Given :
5x²+ 13x + p=0
Roots of the equation reciprocal to each other
To find:
The value of p
Solution:
Given 5x²+ 13x + p=0
Let α and 1/α be the roots of the equation
Compare given equation with ax²+bx + c = 0
a = 5, b = 13 and c = p
As we know Product of the roots of a quadratic equation = c/a
⇒ From above data,
⇒ α (1/α) = p/5
⇒ p/5 = 1
⇒ p = 5
Therefore, the value of p = 5
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