if one root of 5xsq. +13x + k =0 is the reciprocal of the other root then find the value of k
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Product of roots =1
K/5=1 then k=5
CaptainSteverogers:
Sprao534 is ryt
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P(x)= 5x^2+13x+k=0
Given that one root is the reciprocal of the other
==>Roots/zeroes of the polynomial=
a & 1/a
a=5,b=13 & c=k
Product of the roots=c/a
a*1/a=k/5
a/a=k/5
1=k/5
==>K =5
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