Math, asked by ankanapodder91, 8 months ago

if one root of (a-4)x^2+2+1=0 is 1 then the value of a​

Answers

Answered by Kpv5348
3

Answer:

(a - 4) {x}^{2}  + 2 + 1 = 0 \\ (a - 4) {x}^{2}  =  - 3 \\ (a - 4)1 =  - 3 \\ a - 4 =  - 3 \\ a =  - 3 + 4 \\ a = 1

Answered by Anonymous
0

Answer:

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