if one root of a polynomial 2x^2-3x+p is 3 find p and other root
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Answered by
1
Heya !!
P ( X ) = 0
2X² - 3X + P = 0
P ( 3 ) = 0
2 × (3)² - 3 × 3 + P = 0
2 × 9 - 9 + P = 0
18 - 9 + P = 0
P + 9 = 0
P = -9
Sum of zeroes = - B/A
3 + Other root = 3/2
Other root = 3/2-3 = 3-6/2
Other root = -3/2 .
P ( X ) = 0
2X² - 3X + P = 0
P ( 3 ) = 0
2 × (3)² - 3 × 3 + P = 0
2 × 9 - 9 + P = 0
18 - 9 + P = 0
P + 9 = 0
P = -9
Sum of zeroes = - B/A
3 + Other root = 3/2
Other root = 3/2-3 = 3-6/2
Other root = -3/2 .
Answered by
2
Hey!!
p ( x ) = 2x^2 - 3x + p
p ( 3 ) = 2( 3 )^2 - 3 ( 3 ) + p
=> 0 = 18 - 9 + p
=> 0 = 9 + p
=> p = - 9
Sum of zeroes = - b / a
=> 3 + other zero = 3 / 2
=> other zero = 3 / 2 - 3 = - 3 / 2
☆HOPE IT WILL HELPS YOU☆
p ( x ) = 2x^2 - 3x + p
p ( 3 ) = 2( 3 )^2 - 3 ( 3 ) + p
=> 0 = 18 - 9 + p
=> 0 = 9 + p
=> p = - 9
Sum of zeroes = - b / a
=> 3 + other zero = 3 / 2
=> other zero = 3 / 2 - 3 = - 3 / 2
☆HOPE IT WILL HELPS YOU☆
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