If one root of a quadratic equation is 1
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then the quadratic equation can be
Answers
2x² + 2x - 1 = 0 can be the quadratic equation if 1/(1 + √3 is a root
Step-by-step explanation:
Complete and correct question is in attached picture
one root of a quadratic equation is 1/(1 + √3)
1/(1 + √3) = (1 - √3)/(-2) = (√3 - 1)/2
2x² + x - 1 = 0
=> (2x - 1)(x + 1) = 0
so 1/(1 + √3) is not a root
2x² -2x - 1 = 0
=> x = (2 ± √4+ 8)/4 = (1 ± √3)/2
so 1/(1 + √3) is not a root
2x² + 2x + 1 = 0
=> x = (-2 ± √4 - 8)/4 = (-1 ± i)/2
so 1/(1 + √3) is not a root
2x² + x + 1 = 0
=> x = (-1 ± √1 - 8)/4 = (-1 ± √7)/4
so 1/(1 + √3) is not a root
2x² + 2x - 1 = 0
=> x = (-2 ± √4 + 8)/4 = (-1 ± √3)/2
(- 1 + √3)/2 is one of the root
hence 1/(1 + √3) is a root
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