If one root of a quadratic equation is 3 and the sum of the two roots is 0, then find the equation.
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Answer:
One root is 3, so one factor is (x-3).
The product of the roots is 1, so 3a = 1, “a” being the other root, so a = 1/3.
Now we have both roots, and hence both factors:
(X - 3), (X - 1/3)
Multiplying these will give the resulting quadratic equation:
X^2 - 10/3X + 1
Answered by
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Answer:
Given here
Step-by-step explanation:
Let the roots of an quadratic be m,n
thus the quadratic is x^3 - (m+n)x + mn=0
If m = 3, and m + n = 0
⇒ n = -3
thus mn= 3 × (-3) = -9
Thus the quadratic equation becomes :
x^3 -0x + (-9) =0
≡ X^3 -9 =0
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