if one root of a quadratic equation with rational coefficient is 2+√3 then the other root is
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One root is = (-4)+(7)^1/2 ,
Another root will be (-4)-(7)^1/2
Sum of roots =(-4)+(7)^1/2+(-4)-(7)^1/2= -8
Product of roots =(-4)^2-(7^1/2)^2
=16–7
=9
Eq. is:-
x^2-(-8).x+9=0
x^2+8 x+9=0 , Answer.
Another root will be (-4)-(7)^1/2
Sum of roots =(-4)+(7)^1/2+(-4)-(7)^1/2= -8
Product of roots =(-4)^2-(7^1/2)^2
=16–7
=9
Eq. is:-
x^2-(-8).x+9=0
x^2+8 x+9=0 , Answer.
lakshyasingh1491:
va par do chennal h
Answered by
2
2 -
Step-by-step explanation:
Given that,
One root of a quadratic equation having a rational coefficient =
To find,
The other root = ?
Procedure:
As we know,
A quadratic equation having a rational coefficient has conjugate roots.
Thus,
The other root will be 2 -
Learn more: quadratic equation
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