if one root of ax²+2x+7is (-2),then the value of a is?
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Answered by
0
Heya!!!
Let the polynomial ax^2 + 2x + 7 be f (x) .
Then,
Since, (-2) is root or zero of f (x)
F (-2) = 0
=) a (-2)^2 + 2 (-2) + 7 = 0
=) 4a - 4 + 7 = 0
=) 4a + 3 = 0
=) 4a = -3
=) a = -3/4
Hence, the value of a is -3/4.
Hope it helps u.
-)
Let the polynomial ax^2 + 2x + 7 be f (x) .
Then,
Since, (-2) is root or zero of f (x)
F (-2) = 0
=) a (-2)^2 + 2 (-2) + 7 = 0
=) 4a - 4 + 7 = 0
=) 4a + 3 = 0
=) 4a = -3
=) a = -3/4
Hence, the value of a is -3/4.
Hope it helps u.
-)
Answered by
1
Let x= -2
p(x) = ax²+2x+7
putting the value of x.
p(-2) = a (-2)²+2(-2)+7= 0
= 4a-4+7=0
= 4a=-7+4
=4a= -3
= a = -3 /4
p(x) = ax²+2x+7
putting the value of x.
p(-2) = a (-2)²+2(-2)+7= 0
= 4a-4+7=0
= 4a=-7+4
=4a= -3
= a = -3 /4
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