Question

If one root of equation 2x^2+kx-6=0 is 2 find other root nd value of k

Answer 1

Hey

Here is your answer,

substitute the value of x to find the value of k,

2x^2 + kx - 6 = 0
2(2)^2 + 2k - 6 = 0
2 x 4 + 2k - 6 = 0
2k + 8 - 6 = 0
2k + 2 = 0
2k = -2
k = -1

2x^2 -x - 6 = 0
2x^2 - 4x + 3x - 6 = 0
2x ( x - 2 ) + 3 ( x - 2 ) = 0
(X-2) ( 2x+3)=0
X-2 = 0
X = 2
2x + 3 = 0
X = -3/2

Hope it helps you!

Answer 2

Heya !!



P( X ) = 0



2X² + KX - 6 = 0



P ( 2 ) = 0



2 × (2)² + K × 2 - 6 = 0



8 + 2K - 6 = 0


2K = -2


K = -1



----------------------------------

Sum of zeroes = -B/A


2 + other zero = -K/2




4 + 2 × Other root = -(-1)



Other root = 1-4/2

Other root = -3/2.