if one root of equation 2x^2-kx+6=0, then the value of k is
(a) 7
(b) -7
(c) 7/2
(d) -7/2
Answers
Answered by
4
Answer:
K = 7
Step-by-step explanation:
The root is 2
=> When x = 2
=> p(x) = 2× 2^2 - k ×2 + 6 =0
=> 2×4 -2k + 6 =0
=> 8 - 2k + 6 =0
=> 2k = 14
=> k = 7
Similar questions