If one root of equation 2x2
+ax+6=0 is 2 then a=
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Answer:
Value of a = -7
Step-by-step explanation:
Given one root of equation 2x2
one root of equation 2x2+ax+6=0 is 2
Substitute x = 2 , in the equation, we get
=> 2×2²+a×2+6 = 0
=> 8+2a+6=0
=> 2a+14=0
/* Divide each term by 2, we get
=> a+7=0
=> a = -7
Therefore,
Value of a = -7
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